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2 GPa is 2GN/m^2, or 200kN/cm^2, which supports 20Mg. Taking silk density as 1 g/cm^3, that is 20M cm, or 200,000 m, or 20km.

Silk density is actually ~1.37 g/cm^3, so derate the above to 14.6 km. IOW, a silk cable can support 14.6 km of rope hanging below it.

Not close to strong enough for a Space Elevator.



> Not close to strong enough for a Space Elevator.

I thought space elevators were deployed with space tethers, which are held taut by the planet's rotation and centrifugal force. While mutant silk worm silk still may not be strong enough for a space elevator, it shouldn't depend on the weight of the rope hanging below it but instead the on the centrifugal force pulling in the opposite direction, away from the planet's surface.


Space elevators depend utterly on extreme material strength to be possible at all, and on centrifugal force only to stay taut.

They could be practical with known materials on Mars, but there is nothing there worth building one for.


You are sidestepping the fact that in your OP you demonstrated and argued that the silk could not be used for space elevators because it could not support its weight beyond 14.6km, but I argued it would not need to since that weight will be countered by centrifugal force, so whether the silk can be used for a space elevator has nothing whatsoever to do with supporting its own weight, rather, it must support the centrifugal force.

If the silk only need be kept "only" taut, its weight will be perfectly balanced against centrifugal force, so in effect the silk will be weightless. But my suspicion is the tether would necessarily need to be kept taut with extra force, not "only" taught, but with force to put stress on the silk tether pointing outwards and upwards.

I have no idea how one would calculate the required centrifugal force, but perhaps you'll do us all the favor and determine whether or not the silk would be strong enough without being distracted by the weight of all the silk, which is irrelevant due to it being cancelled by centrifugal force.


The correct figure, as noted elsewhere, is 146 km.

But literally the only thing holding up almost all of the span from geosynchronous orbit down to the ground is the pure strength of the cable. Centrifugal force would act usefully mainly on parts of the cable that extend out past geosynchronous orbit, to support the whole structure through tension in the cable. The cable inside that orbit would absolutely not be weightless. Its weight per unit mass is of course lower close to geosynchronous orbit, but most of the cable is very far from it.


Effectively weightless. The weight of any part of the tether must be entirely counteracted by centrifugal force, otherwise the weight of the tether would pull everything to the ground.


"Counteracted" by force through tension in the cable. Which relies on the cable holding up its own weight. So, in no way "effectively weightless", unless you consider a regular bridge deck weightless because cables are holding it up.


> "Counteracted" by force through tension in the cable. Which relies on the cable holding up its own weight. So, in no way "effectively weightless", unless you consider a regular bridge deck weightless because cables are holding it up.

No. That is ridiculous and wrong.

The cable is not holding up its own weight, the centrifugal force is. The tension comes from the anchor point and the centrifugal force only. Weight is entirely counteracted and is no longer a consideration.


Let's ignore gravity for a moment.

Think of a rotating chain in space, the chain is weightless, but each ring needs to apply enough centripetal force to counter the centripetal force.

Lets focus on the barycenter of the chain.

The centripetal force is limited by the strength of the chain; the centrifugal force is a function of rotation speed, length of the chain, and linear density of the chain.

this means that for any combination of chain type and rotation speed if the chain gets too long it will break.

With a geostationary space elevator you need to build a part of it over geostationary orbit and a part of it below geostationary orbit. the part above will pull the part below and make it "float".

The problem is that the part below needs to be ~100 km long and has still has a weight.

Think of the section of the tether at geostationary orbit as a giant weightless chain link.

The issue is not having that chain link remain suspended, the problem is to have it not break while trying to balance the huge forces.


> The problem is that the part below needs to be ~100 km long and has still has a weight

And in order for a space tether to work at all, that weight must be negated by centrifugal force or the entire thing will collapse to the ground.


the centrifugal force and the weight are applied in different points.

all the ~100km of tether below geostationary orbit will have positive net weight by definition. All this weight must be held by tensile strength, whether it comes from a fleet of rockets or centrifugal force is irrelevant.

Again the hard thing is not making it float, geostationary satellites do this already, the hard thing is building a 100km long satellite.

EDIT: said another way consider a chain being pulled apart by two tractors. All forces on the chain cancel each other yet some chains will break and some will not.

Forces are first applied, then propagated, then (vectorially) summed. If the material cannot handle the forces applied it will break.

If you happen to have seen those "Hydraulic press against X" videos you can see how it is not enough to have forces cancel each other in different points.

And to be clear about how this is relevant: for (at least) the first 50km or so the centrifugal force is negligible, so even if

weight + centripetal_force = 0

you have

|weight| + |centripetal_force| = fuckton of force


I leave it to someone else to explain things to you. I can only pray that no one's safety depends on your understanding of physics.


You've abandoned reason to employ an invincible ignorance fallacy as well as an ad hominem.


You may comfort yourself with believing that. Be my guest. Good day.


That's still only the very first step to building a Space Elevator. And, the product, if it had those properties (when deployed in the wild) would find more profitable use in terrestrial applications.

We will be burning rocket fuel to get to space for the foreseeable future. Better to launch enough to build in-space processing facilities if you're really committed to dual-homing humanity or making space travel more cost effective.


You lost a zero in there, so more like 146km.


Not enough for a space elevator on Earth, but definitely in the range you need for very long suspension bridges -- think in terms of railway bridges over the English Channel, the Straits of Gibraltar, the Irish Sea, and (with causeways/island hopping) the Bering Straits.


Examples here, one can sort by breaking length: https://en.wikipedia.org/wiki/Specific_strength

(2 GPa) / (1400 kg/m^3 x 10 m/s^2) = (2e9 N/m^2)/(1.4e4 N/m^3) = (2e5/1.4) m = 140 000 m = 140 km

P = F/A, F = M x g, M = A x L x rho

L = M/(A x rho) = (F/g)/(A x rho) = (F/A)/(g x rho) = P / (g x rho)


Oops, tx. Seemed low.


Space elevators are lame. Launchloops and orbital rings are where it's at! :D


Orbital rings like circular skyhooks that are much easier to schedule pickup on, and have much friendlier structural stress characteristics, seem not to be written about as much as they ought to be.

If by orbital ring you mean a band girdling the planet and rotating well above orbital speed, magnetically coupled to and supporting stationary structures that reach ground level... I don't see any value in discussing those in this century.




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